0=3t^2+20t-175

Solution for 0=3t^2+20t-175 equation:

0=3t^2+20t-175

We move all terms to the left:

0-(3t^2+20t-175)=0

We add all the numbers together, and all the variables

-(3t^2+20t-175)=0

We get rid of parentheses

-3t^2-20t+175=0

a = -3; b = -20; c = +175;
Δ = b2-4ac
Δ = -202-4·(-3)·175
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-50}{2*-3}=\frac{-30}{-6}
=+5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+50}{2*-3}=\frac{70}{-6}
=-11+2/3
$